Java XML Grepper

You want to get a value from your xml file using XPath? Then this is for you. Easily grep the version from your POM.

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Is this for me?

If you want to grep e.g. the version of a pom.xml file to commandline then this is for you.

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>io.codeclou</groupId>
  <artifactId>java-xml-grepper</artifactId>
  <version>1.4.5</version>
</project>

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Usage

With current folder containing a pom.xml file and you want to print out the version on commandline. The -x parameter accepts XPath expressions that can be cast to String.

# INSTALL
curl -L -o java-xml-grepper.jar \
     https://github.com/codeclou/java-xml-grepper/releases/download/1.0.0/java-xml-grepper.jar

# RUN
java -jar java-xml-grepper.jar \
     -f pom.xml \
     -x /project/version
     
# PRINTS (example)
1.0.1

If something happens like parsing errors, file not found a.s.o the exit code will be 1. Otherwise the exit code will be 0 and it will only print the grepped output.

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Demo

git clone https://github.com/codeclou/java-xml-grepper.git src
cd src

curl -L -o java-xml-grepper.jar \
     https://github.com/codeclou/java-xml-grepper/releases/download/1.0.0/java-xml-grepper.jar

java -jar java-xml-grepper.jar \
     -f pom.xml \
     -x /project/version

# Should print the version

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License

MIT © Bernhard Grünewaldt